Case 2 -  8% shortening at strain rate of 0.04/Ma

In this exercise a lower displacement rate for the tectonic event will be considered (strain rate of 0.04/Ma) with the expectancy of a lesser overpressure than Case1.  This will be achieved by considering the same amount of shortening over a longer time period of 2.0Ma.  To this end, the usage of restart files will be employed, thus eliminating the need to rerun the sedimentation stages again.

 

To perform this exercise it is required:

1.To copy the  "hm_005_Case1_stage_11.rst" generated after deposition of the last layer from the previous example into a new folder.

2.Copy the restart datafile to the new folder and then modify it as shown below.

 

 

Data File

 

 

* Restart_Read_data

! ---------------------------------

 Restart_file_name      "hm_005_Case1_stage_11.rst"

 

 

 

!---------------------------------------------------

! Stage 12 Tectonic displacement

!---------------------------------------------------

 

* Global_loads NUM=1

! ---------------------------------

 Name          "Displacement"

 Prescribed_displacement IDM=2 JDM=1

  /Set 1/  -80.0    0.0

 Pres_displacement_geom_set        IDM=1

   "East"

 Pres_displacement_geom_ass        IDM=1

    1

 

* Time_curve_data NUM=1

! ---------------------------------

 Name          "Displacement"

 Time_curve    IDM=2

   44.0 46.0

 Load_factor   IDM=2

   0.0   1.0

 

* Load_case_control_data

! ---------------------------------

 Loadcases         IDM=1

  1

 Active_load_flags IDM=1

  2

 

 

* Control_data

! ---------------------------------

 Control_title          "Compression"

 Solution_algorithm                4  

 Target_number_time_steps        200

 Duration                       2.0

 Initial_time_increment       0.002

 Screen_message_frequency         10

 Output_time_plotfile           0.4

 Output_frequency_plotfile        -1

 Output_frequency_restart         -1

 

1Read the restart file written after the final sedimentation stage, i.e. "hm_005_Case1_stage_11.rst".

 

 

 

 

 

 

 

 

 

 

 

 

 

2The time on the Time_curve_data is modified so that the displacement occurs between 44 and 46 Ma (0.08 strain/2 Ma = 0.04/Ma strain rate).

 

 

 

 

 

 

 

 

 

 

3Define the control data to perform 1000 flow steps over the stage duration of 2.0Ma and 200 mechanical steps per flow step, i.e.:

a)Target_number_time_steps set to 200 defines the target number of mechanical steps per flow step.

b)Initial_time_increment set to 0.002 defines the flow step time increment, i.e. 1000 flow steps over 2.0 Ma duration.

 

 

Click to expand/collapseResults